For a steady flow, the velocity field is V^{\to} = (−x^{2} + 3y) i^{\^} + (2xy) j^{\^} . The magnitude of the acceleration of a particle at (1, -1) is

GATE Mechanical Engineering (ME) 2017 Shift 1 Solved Paper

Question : 42 of 65

Marks: +1, -0

For a steady flow, the velocity field is

V↖{→} = (−x^{2} + 3y) i↖{\^} + (2xy) j↖{\^}

. The magnitude of the acceleration of a particle at (1, -1) is

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