GATE Mechanical Engineering (ME) 2018 Shift 1 Solved Paper

Question : 42 of 65

Marks: +1, -0

The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is

R=1-e^{-(n+1)}

where n represents the strain hardening coefficient. For the case of a perfectly plastic material,

R

Solution:

Perfectly plastic material implies that strain hardening coefficient

{n}

is zero. Hence

R=\;{A_{o}}/{A_{f}}=1-e^{-1}=1-\;{1}/{e}=0.6321

Go to Question:

Prev Question

Next Question