GATE Mechanical Engineering (ME) 2018 Shift 1 Solved Paper

Question : 61 of 65

Marks: +1, -0

Block P of mass

2 {kg}

slides down the surface and has a speed

20 {m} {/} {s}

at the lowest point, Q where the local radius of curvature is

2 {m}

as shown in the figure. Assuming

g=10 {m} {/} {s}^{2}

, the normal force (in

{N}

) at

{Q}

is__________ (correct to two decimal places).

Solution:

m=2 {kg}, g=10 {m} \/ {s}^{2}

F B D

of mass

P

at Point

Q

N-m g=m a_{r}

at no slip condition.

N=m g+\;{m v^{2}}/{R}=2 × 10+\;{2 × 20 × 20}/{2}=420 {N}

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