A circular hole of 25 {mm} diameter and depth of 20 {mm} is machined by EDM process. The material removal rate (in {mm}^{3} {/ } {\min} ) is expressed as 4 \times 10^{4} I T^{-1.23} where I=300 {A} and the melting point of the material T=1600^{\circ} {C}. The time (in minutes) for machining this hole is _________ (correct to two decimal places).

GATE Mechanical Engineering (ME) 2018 Shift 2 Solved Paper

Question : 47 of 65

Marks: +1, -0

A circular hole of

25 {mm}

diameter and depth of

20 {mm}

is machined by EDM process. The material removal rate (in

{mm}^{3} {/ } {min}

) is expressed as

4 × 10^{4} I T^{-1.23}

where

I=300 {A}

and the melting point of the material

T=1600^{∘} {C}

. The time (in minutes) for machining this hole is _________ (correct to two decimal places).

Solution:

M R R=4 × 10^{4} × 300 × 1600^{-1.23}=1374.4 {mm} 3 {/} {min}

Time required

=\;{9817.477}/{1374.4}

=7.1431 min.

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