GATE Mechanical Engineering (ME) 2019 Shift 1 Solved Paper

Question : 65 of 65

Marks: +1, -0

In ASA system, the side cutting and end cutting edge angles of a sharp turning tool are

45^{∘}

and

10^{∘}

, respectively. The feed during cylindrical turning is

0.1 {mm} {/} {rev}

. The center line average surface roughness (in

µ {m}

, round off to one decimal place) of the generated surface is _________

Solution:

SCEA

=45^{∘}

and ECEA

{}=10^{∘}

Feed (f)

=0.1 {mm} {/} {rev}

center line average surface roughness

R_{a}=

\;{f}/{4(\tan \SCEA+\cot \ECEA)}=\;{0.1}/{4(\tan 45^{∘}+\cot 10^{∘})}

=\;{0.1}/{4(1+5.67)}=\;{0.1}/{26.68}=3.74 × 10^{-3} {mm}=3.74 µ {m}

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