IBPS PO Exam 2013 Solved Paper

From I and II.
Length = 3x = 48 m
∴ x = 16
Breadth = 2x = 32 m
Hence, Area of floor = 48 × 32
Cost of flooring = 48 × 32 × 850 = ₹ 1305600
From I and III, 2(l + b) = 160
⇒ 2(3x + 2x) = 160 Þ 10x = 160
∴ x = 16
∴ Length = 3 × 16 = 48 m
Breadth = 2 × 16 = 32 m
Cost of flooring = (48 × 32) × 850 = ₹ 1305600
Similarly, from II and III, we can find I = 48 m and b = 32 m
and Total cost of flooring = ₹ 1305600