IBPS PO Exam 2014 Solved Paper

I. 4x2 – 24x + 20 = 0
x2 – 6x + 5 = 0
x2 – 5x – x + 5 = 0
x (x – 5) –1 (x – 5) = 0
(x – 5) (x – 1) = 0
x = 5 , 1
II. y2 – 13y + 42 = 0
y2 – 7y – 6y + 42 = 0
y (y – 7) – 6 (y – 7) = 0
(y – 7) (y – 6) = 0
y = 7, 6
Hence, y > x.