IBPS SO Prelims Exam Model Paper 2

Follow BODMAS rule to solve this question, as per the order given below,
Step-1: Parts of an equation enclosed in ‘Brackets’ must be solved first.
Step-2: Any mathematical ‘Of’ or ‘Exponent’ must be solved next.
Step-3: Next, the parts of the equation that contain ‘Division’ and ‘Multiplication’ are calculated.
Step-4: Last but not the least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated.
676 × 21 ÷ 273 + (5041)

1

2

– 625/√? = 98
⇒

(676×21)

273

+ (712)

1

2

– 625/√? = 98
⇒

676

13

+ 71 – 625/√? = 98
⇒

676

13

+ 71 – 98 = 625/√?
⇒ 52 + 71 – 98 = 625/√?
⇒ 25 = 625/√?
⇒ √? =

625

25

∴ ? = 625