IBPS SO Prelims Exam Model Paper 9

i. x2 – 25x + 154 = 0
⇒ x2 – 14x – 11x + 154 = 0
⇒ x(x – 14) – 11(x – 14) = 0
⇒ (x – 14) (x – 11) = 0
⇒ x = 14, 11
ii. y2 – 24y + 135 = 0
⇒ y2 – 15y – 9y + 135 = 0
⇒ y(y – 15) – 9(y – 15) = 0
⇒ (y – 15) (y – 9) = 0
⇒ y = 15, 9∴ Relationship between x and y cannot be established.