Let α and β be the roots of x^2 – 6x – 2 = 0, with α > β. If a_n = \alpha^n-\beta^n for n ≥ 1, then the value of {a_{10}-2a_8}/{2a_9} is [JEE Adv 2011 P1]

IIT JEE Advanced 2011 Paper 1

Section: Mathematics

Question : 52 of 69

Marks: +1, -0

Let α and β be the roots of x2 – 6x – 2 = 0, with α > β. If an = αn−βn for n ≥ 1, then the value of

a10−2a8

2a9

[JEE Adv 2011 P1]

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