IIT JEE Advanced 2012 Paper 1

Considering the reaction (replace α-particle by

4

‌

2

He)

63

‌

29

Cu+

1

‌

1

H → 601n+

4

‌

2

He+211H+X
Equating mass numbers on both the sides, we get
63 +1 = 1× 6 + 4 ×1+1× 2 + X = 64 -12 = 52
Equating atomic numbers on both the sides, we get
29 +1 = 6 × 0 + 2 + 2 ×1+ Y⇒Y = 30 - 4 = 26
So, the element is 26
52 Fe and iron is a d-block element, which belongs to Group 8 of the periodic table.