If A(\alpha, \beta)=[\table \cos \alpha , \sin \alpha , 0 ; -\sin \alpha , \cos \alpha , 0 ; 0 , 0 , e^{\beta}], then

{A}(\alpha, \beta)^{'}= {A}(-\alpha, \beta)

{A}(\alpha, \beta)^{-1}= {A}(-\alpha,-\beta)

Adj( {A}(\alpha, \beta))= {e}^{\beta} {A}(-\alpha,-\beta)