For the equation \frac{40}{x-1}-\frac{160}{x-4}-\frac{200}{x-5}+\frac{320}{x-8}=6 x^{2}-27 x

Number of real solution of above equation is 3

If E denotes the product of non-zero or complex roots of equation, then sum of divisors of E is 2904

It S denotes the set of all real roots of equation then, sum of elements of S taken two at a time is 81

If \alpha_{1}, \alpha_{2} \in R be two roots of equation such that \log _{\alpha_{2}}(2 \alpha_{1}) is defined it must be 1 .

JEE Advanced 2020 Full Test 5 Paper 2

Question : 48 of 54

Marks: +1, -0

For the equation ‌

x−1

−‌

160

x−4

−‌

200

x−5

+‌

320

x−8

=6x2−27x

Number of real solution of above equation is 3
If E denotes the product of non-zero or complex roots of equation, then sum of divisors of E is 2904
It S denotes the set of all real roots of equation then, sum of elements of S taken two at a time is 81
If α1,α2∈R be two roots of equation such that logα2(2α1) is defined it must be 1 .

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