\int {x^{2}-1}/{x^{3} \sqrt{2 x^{4}-2 x^{2}+1}} d x is equal to

Correct Answer is : 12x2√2x4−2x2+1+c

\frac{1}{x^{2}} \sqrt{2 x^{4}-2 x^{2}+1}+c

\frac{1}{x^{3}} \sqrt{2 x^{4}-2 x^{2}+1}+c

\frac{1}{x} \sqrt{2 x^{4}-2 x^{2}+1}+c

\frac{1}{2 x^{2}} \sqrt{2 x^{4}-2 x^{2}+1}+c

JEE Advanced 2020 Full Test 6 Paper 2

Question : 48 of 54

Marks: +1, -0

∫‌

x2−1

x3√2x4−2x2+1

dx is equal to

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