Three waves \\Psi_{1}={A} \sin [{Kx}-\\omega{t}), \\Psi_{2}=3 \\sqrt{2} {A} \sin ({kx}-\\omega{t}+\ϕ) and \\Psi_{3}=4 {A} \sin ({kx}-\\omega{t}+\\pi\/ 2) are superimposed. If resultant wave is given by \\Psi=R \.\sin (k x-\\omegat+\\pi\/ 2). Where R is some constant. Find \ϕ (in degrees).

JEE Advanced 2021 Full Test 3 Paper 1

SECTION – C (Numerical Answer Type)
This section contains 06 questions. The answer to each question is a NUMERICAL VALUE. For each question, enter the correct numerical value (in decimal notation, truncated/rounded‐off to the second decimal place; e.g. XXXXX.XX).

Question : 16 of 54

Marks: +1, -0

Three waves Ψ1=A‌sin[Kx−ωt), Ψ2=3√2A‌sin(kx−ωt+ϕ) and Ψ3=4A‌sin(kx−ωt+π∕2) are superimposed. If resultant wave is given by Ψ=R.sin(kx−ωt+π∕2). Where R is some constant. Find ϕ (in degrees).

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