If f (x) = \{\table -x- \pi/2 , x \pi - \pi/2 ; - cosx , -\pi/2 < x \leq 0 ; x - 1 , 0 < x \leq 1 ; \ln x , x > 1 , then [JEE Adv 2011 P2]

f (x) is continuous at x = −π/2.

f (x) is not differentiable at x = 0.

f (x) is differentiable at x = 1.

f (x) is differentiable at x = −3/2.

Limits, Continuity and Differentiability

Section: Mathematics

Question : 44 of 51

Marks: +1, -0

If f (x) = {

−x−

xπ−

−cosx

−

<x≤0

x−1

0<x≤1

ln‌x

x>1

, then

[JEE Adv 2011 P2]

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