JEE Advanced Model Paper 1 with solutions for online practice

Any plane through the second line is 22(2 + 3k) + (1 + k) + (1 + 2k) = 0If this is parallel to the first line, then (2 + 3k) + (1 + k) + (1 + 2k) = 0
⇒ k = −

2

3

⇒ Plane is 2x + y + z - 1

2

3

(3x + y + 2z - 2) = 0 or y - z + 1 = 0
The required SD must be distance of this plane from any point on the line
x = y = z say (1 , 1 , 1)
⇒ SD =

|1−1+1|

√02+12+(−1)2

=

1

√2