JEE Advanced Model Paper 15 with solutions for online practice

Passage-3

If a function (continuous and twice differentiable) is always concave upward in an interval, then its graph lies always below the segment joining extremities of the graph in that interval and vice-versa.

Question : 54 of 60

Marks: +1, -0

Let f (x) , f'(x) and f''(x) are all positive ∀ x ∊ [0, 7] . If f−1 (x) exists , then 3 f−1 (4) - f−1 (2) - 2f−1 (5) is

always positive
always negative
non-negative
non-positive

Validate

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