JEE Advanced Model Paper 4 with solutions for online practice

Any plane through the second line is 22(2 + 3k) + (1 + k) +(1 + 2k) = 0
If this is parallel to the first line, then (2 + 3k) + (1 + k) + (1 + 2k) = 0 ⇒ = −

2

3

⇒ Plane is 2x + y + z - 1 −

2

3

(3x + y + 2z - 2) = 0 or y - z + 1 = 0
The required SD must be distance of this plane from any point on the line
x = y = z say (1, 1, 1) ⇒ SD =

|−1+1|

√02+12+(−1)2

=

1

√2