JEE Advanced Model Paper 7 with solutions for online practice

O2(g) + 4H(g)+ + 4e− → 2H2O(l) ; E° = 1.23 V
S2O8(aq)2− + 2e− → 2SO44(aq)2− ; E° = 2.01 V
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Since the EMF of cell is negative, the reverse reaction is spontaneous.
Hence : water is oxidized to O2 & S2O82− is reduced to SO42−