JEE Main 08 Apr 2018 Code A Solved Paper

Section: Mathematics
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Question : 65 of 90
 
Marks: +1, -0
If the system of linear equations
x+ky+3z=0
3x+ky−2z=0
2x+4y−3z=0
has a non-zero solution (x, y, z), then
xz
y2
is equal to
[Main 8 April 2018]
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