JEE Main 10 Apr 2019 Paper 1 Solved Paper

Section: Mathematics

Question : 76 of 90

Marks: +1, -0

ABC is a triangular park with AB = AC = 100 m. A vertical tower is situated at the midpoint of BC. If the angles of elevation of the top of the tower at A and B are cot−1(3√2) and cosec−1(2√2) respectively, then the height of the tower (in metres) is:

[10 Apr 2019 Shift 1]

25
10√5
100
3√3
20

Validate

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