JEE Main 12 Jan 2019 Shift 1 Solved Paper

Section: Mathematics

Question : 41 of 90

Marks: +1, -0

let C1 and C2 be the centres of the circles x2+y2 - 2x - 2y - 2 = 0 and x2+y2 - 6x - 6y + 14 = 0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral PC1QC2 is :

[12 Jan 2019 Shift 1]

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