JEE Main 15 Apr 2018 Shift 2 Solved Paper

Section: Chemistry
© examsiri.com
Question : 54 of 90
 
Marks: +1, -0
∆fG∘ at 500 K for substance ' S ' in liquid state and gaseous state are +100.7kcalmol−1 and +103 kcal mol−1, respectively. Vapour pressure of liquid ' S ' at 500 K is approximately equal to: (R=2calK−1mol−1)−
[15 Apr 2018 Shift 2]
Go to Question: