Home Back

JEE Main 16 March 2021 Shift 1 Solved Paper

Section: Chemistry
© examsiri.com
Question : 51 of 90
 
Marks: +1, -0
For the reaction, A(g)⇌B(g) at 495K, ∆,G∘=−9.478kJmol−1. If we start the reaction in a closed container at 495K with 22 millimoles of A, the amount of B is the equilibrium mixture is ......... millimoles (Round off to the nearest integer). [R=8.314Jmol−1K−1,ln‌10=2.303]
[16 Mar 2021 Shift 1]
  • Your Answer:
Validate
Go to Question:
Prev Question
Next Question