JEE Main 16 March 2021 Shift 1 Solved Paper

Section: Mathematics

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Question : 76 of 90

Marks: +1, -0

Let [x] denote greatest integer less than or equal to x. If for n∈N,(1−x+x3)n=

3n

∑

j=0

ajxj, then

∑

j=0

[‌

3n

2

]a2j+4‌

∑

j=0

[‌

3n−1

2

]a2j+1 is equal to

[16 Mar 2021 Shift 1]

2
2n−1
1
n

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