Home Back

JEE Main 16 March 2021 Shift 1 Solved Paper

Section: Mathematics
© examsiri.com
Question : 87 of 90
 
Marks: +1, -0
If the normal to the curve y(x)=
x
∫
0
(2t2−15t+10)dt at a point (a,b) is parallel to the line x+3y=−5,a>1, then the value of |a+6b| is equal to.........
[16 Mar 2021 Shift 1]
  • Your Answer:
Validate
Go to Question:
Prev Question
Next Question