0.01 moles of a weak acid {HA}(K_{a}=2.0 \times 10^{-6}) is dissolved in 1.0 {L} of 0.1 {M} {HCl} solution. The degree of dissociation of {HA} is ...... \times 10^{-5} (Round off to the nearest integer). [Neglect volume change on adding HA. Assume degree of dissociation ≪

JEE Main 17 March 2021 Shift 1 Solved Paper

Section: Chemistry

Question : 52 of 90

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0.01 moles of a weak acid HA(Ka=2.0×10−6) is dissolved in 1.0L of 0.1MHCl solution. The degree of dissociation of HA is ...... ×10−5 (Round off to the nearest integer). [Neglect volume change on adding HA. Assume degree of dissociation ≪<1 ]

[17 Mar 2021 Shift 1]

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‌	HA	⇌	H+(aq)	+	A−(aq)
t=0	0.01	‌	0.1	‌	0
t=t‌eq ‌	0.01−0.01−α	‌	0.1+0.01α	‌	0.01α