JEE Main 17 March 2021 Shift 1 Solved Paper

Section: Mathematics
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Question : 67 of 90
 
Marks: +1, -0
If A=(
0sin‌α
sin‌α0
)
and det(A2−‌
1
2
f
)
=0
, then a possible value of α is
[17 Mar 2021 Shift 1]
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