JEE Main 18 March 2021 Shift 1 Solved Paper

Given
The mass of the bullet, m=0.1kg
The initial velocity of the bullet before hitting the wooden, u=10m∕s
The final velocity of the bullet after hitting the wooden, v=0
The distance travelled by the bullet before coming to the rest, s=50cm
Using the equation of the motion,
v2−u2=2as
⇒‌‌02−(10)2=2a(0.50)
⇒‌‌a=−100m∕s2
The uniform retardation of the bullet is 100m∕s2
The magnitude of the effective retarding force on the bullet,
F=ma F=0.1(−100)
F=−10N
Hence, the value of x to the nearest integer is 10 .