JEE Main 18 March 2021 Shift 1 Solved Paper
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Question : 54 of 90
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For the reaction,
C 2 H 6 ⟶ C 2 H 4 + H 2 (Round off to the nearest integer). [Given : Bond enthalpies in k J m o l m − 1 : C − C = 347 , C = C = 611 ; C − H = 414 ; H − H = 436
[18 Mar 2021 Shift 1]
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