JEE Main 18 March 2021 Shift 1 Solved Paper

Section: Mathematics

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Question : 88 of 90

Marks: +1, -0

If f(x)=∫‌

5x8+7x6

(x2+1+2x7)2

dx,(x≥0),f(0)=0 and f(1)=‌

1

K′

then the value of K is

[18 Mar 2021 Shift 1]

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