For {p}>0, a vector {{v^{\to}}}_{2}=2 \stackrel{\^}{{i}}+({p}+1) {{j^{\^}}} is obtained by rotating the vector \overrightarrow{{v}}_{1}=\\sqrt{3} {p} \stackrel{\^}{{i}}+{{j}}^{\^} by an angle\\theta about origin in counter clockwise direction. If\tan \\theta={(\\alpha\\sqrt{3}-2)}/{(4 \\sqrt{3}+3)}, then the value of \\alpha is equal to _________. [20 Jul 2021 Shift 2]

JEE Main 20 July 2021 Shift 2 Solved Paper

Section: Mathematics

Question : 84 of 90

Marks: +1, -0

For p>0, a vector

→

2=2

+(p+1)

is obtained by rotating the vector

→

1=√3p

by an angleθ about origin in counter clockwise direction. Iftan‌θ=

(α√3−2)

(4√3+3)

, then the value of α is equal to _________.

[20 Jul 2021 Shift 2]

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