JEE Main 22 Jan 2026 Shift 1 Paper Solved Paper

Section: Chemistry
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Question : 74 of 75
 
Marks: +1, -0
The temperature at which the rate constants of the given below two gaseous reactions become equal is ____ K. (Nearest integer)
X→Y,‌k1=106e‌
−30000
T

P→Q,‌k2=104e‌
−24000
T


Given :ln‌10=2.303
[22 Jan 2026 Shift 1]
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