Let {y}={y}({x}) be the solution of the differential equation {\cosec}^{2} x d y+2 d x=(1+y \cos 2 x) {\cosec}^{2} x d x, withy(\frac{\\pi}{4})=0 . Then, the value of (y(0)+1)^{2} is equal to: [22 Jul 2021 Shift 2]

JEE Main 22 July 2021 Shift 2 Solved Paper

Section: Mathematics

Question : 64 of 90

Marks: +1, -0

Let y=y(x) be the solution of the differential equation cosec2xdy+2dx=(1+y‌cos‌2‌x) cosec2xdx, withy(

)=0. Then, the value of (y(0)+1)2 is equal to:

[22 Jul 2021 Shift 2]

Go to Question:

Prev Question

Next Question