JEE Main 24 Feb 2021 Shift 1 Solved Paper

Al2O3 (aluminium oxide) was leached with alkali to get Na[Al(OH)4](X) (sodium aluminate). The solution of sodium aluminate when passed through gas Y, i.e. carbon dioxide (CO2) forms (Al2O3⋅xH2O)(Z).
Complete reactions are as follows

Al2O3

Aluminium‌oxide

+

2NaOH(aq)

Sodium‌hydroxide

+3H2O(l)⟶
2Na[

Al

(X)

(OH)4](aq)

+CO2(Y)

⟶

Al2O3⋅xH2O

(Z)

+

2NaHCO3

Sodium‌bicarbonate

Hence, X‌‌=Na[Al(OH)4]
Y‌‌=CO2
Z‌‌=Al2O3⋅xH2O