JEE Main 24 Feb 2021 Shift 1 Solved Paper

Section: Mathematics

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Question : 66 of 90

Marks: +1, -0

lim

x→0

‌

∫

0

x2(sin‌√t)dt

x3

is equal to

[24 Feb 2021 Shift 1]

‌
2
3
‌
3
2
‌
1
15
0

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