JEE Main 25 Feb 2021 Shift 1 Solved Paper

Section: Mathematics

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Question : 62 of 90

Marks: +1, -0

If 0<θ,φ<‌

π

2

,x=

∞

∑

n=0

cos2nθ,y=

∞

∑

n=0

sin2nφ and z=

∞

∑

n=0

cos2nθ⋅sin2nφ, then

[25 Feb 2021 Shift 1]

xy−z=(x+y)z
xy+yz+zx=z
xyz=4
xy+z=(x+y)z

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