Let {f}({x})=3 \sin ^{4} {x}+10 \sin ^{3} {x}+6 \sin ^{2} {x}-3,{x} \\in[-\frac{\\pi}{6}, \frac{\\pi}{2}] . Then, {f} is : [25 Jul 2021 Shift 1]

Correct Answer is : decreasing in (−π6,0)

increasing in (-\frac{\\pi}{6}, \frac{\\pi}{2})

decreasing in (0, \frac{\\pi}{2})

increasing in (-\frac{\\pi}{6}, 0)

decreasing in (-\frac{\\pi}{6}, 0)

JEE Main 25 July 2021 Shift 1 Solved Paper

Section: Mathematics

Question : 62 of 90

Marks: +1, -0

Let f(x)=3sin4x+10sin3x+6sin2x−3,x∈[−

]. Then, f is :

[25 Jul 2021 Shift 1]

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