JEE Main 25 June 2022 Shift 2 Solved Paper

Section: Chemistry

Question : 85 of 90

Marks: +1, -0

A solution of Fe2(SO4)3 is electrolyzed for ' x ' min with a current of 1.5A to deposit 0.3482g of Fe. The value of x is [nearest integer]
Given : 1F=96500Cmol−1
Atomic mass of Fe=56gmol−1

[25-Jun-2022-Shift-2]

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