JEE Main 26 Feb 2021 Shift 1 Solved Paper

Number of radial nodes =(n−I−1)
[ n= principal quantum number, I= az imuthal quantum number] Number of angular nodes =1
(a) 3p(n=3,I=1)⇒1‌‌1
(b) 4f(n=4,I=3)⇒0‌‌3
(c) 4d(n=4,I=2)⇒1‌‌2
(d) 5d(n=5,I=2)⇒2‌‌2
So, 5d-orbital has two radial as well as two angular nodes (option-d). Note I=0 for s-orbital, I=1 for p-orbital, I=2 for d-orbital and I=3 for f−orbital.