JEE Main 26 Feb 2021 Shift 1 Solved Paper

X⟶Y, it is an exothermic reaction whose ∆E or ∆H=−20kJmol−1Given, activation energy of the forward reaction (X→Y),
Eaf=30kJmol−1
Activation energy of the backward or reverse reaction (Y→X), Eab can be calculated as,
‌∆H=Eaf−Eab
⇒‌Eab=Eaf−∆H=30−(−20)=50kJmol−1