The hydrogen electrode is dipped in a solution of {\pH}=3 at 25^{\circ} {\C}. The potential of the electrode will be____ \times 10^{-2} {\V}. ( {2.303 {\RT}}/{ {\F}}=0.059 {\V}) [27-Jan-2024 Shift 2]

JEE Main 27-Jan-2024 Shift 2 Solved Paper

Section: Chemistry

Question : 88 of 90

Marks: +1, -0

The hydrogen electrode is dipped in a solution of pH=3 at 25∘C. The potential of the electrode will be____ ×10−2V.
(‌

2.303‌RT

=0.059V)

[27-Jan-2024 Shift 2]

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