Let {{a}}^{\to}=\stackrel{\^}{{i}}+{{j}}^{\^}+2 \stackrel{\^}{{k}} and {{b^{\to}}}=-{{i}}^{\^}+2 {{j}}^{\^}+3 {{k}}^{\^}. Then the vector product (\overrightarrow{{a}}+\overrightarrow{{b}}) \\times((\overrightarrow{{a}} \\times((\overrightarrow{{a}}-{{b^{\to}}}) \\times \overrightarrow{{b}})) \\times\overrightarrow{{b}}) is equal to: [27 Jul 2021 Shift 1]

Correct Answer is : 7(34^i−5^j+3^k)

5(34 {{i}}^{\^}-5 \stackrel{\^}{{j}}+3 \stackrel{\^}{{k}})

7(34{{i}}^{\^}-5 {{j}}^{\^}+3 {{k^{\^}}})

7(30\stackrel{\^}{{i}}-5{{j}}^{\^}+7 \stackrel{\^}{{k}})

5(30 \stackrel{\^}{i}-5 \stackrel{\^}{j}+7 \stackrel{\^}{k})

JEE Main 27 July 2021 Shift 1 Solved Paper

Section: Mathematics

Question : 63 of 90

Marks: +1, -0

Let

→

and

→

=−

. Then the vector product (

→

)×((

→

×((

→

−

→

)×

→

)) ×

→

) is equal to:

[27 Jul 2021 Shift 1]

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