The rate constant for a first order reaction is given by the following equation: \ln k=33.24-\frac{2.0 \times 10^4 K}{T} The activation energy for the reaction is given by ____{\kJ} {\mol}^{-1}. (In nearest integer) (Given : {\R}=8.3 {\JK}^{-1} {\mol}^{-1} ) [27-Jun-2022-Shift-1]

JEE Main 27 June 2022 Shift 1 Solved Paper

Section: Chemistry

Question : 86 of 90

Marks: +1, -0

The rate constant for a first order reaction is given by the following equation:
ln‌k=33.24−‌

2.0×104K

The activation energy for the reaction is given by ____kJ‌mol−1. (In nearest integer) (Given : R=8.3JK−1mol−1 )

[27-Jun-2022-Shift-1]

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