JEE Main 28 Jan 2026 Shift 2 Paper Solved Paper
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Question : 74 of 75
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Two positively charged particles m 1 and m 2 have been accelerated across the same potential difference of 200 keV as shown below.
[Given mass ofm 1 = 1 amu and m 2 = 4 amu]
The deBroglie wavelength ofm 1 will be x times of m 2 . The value of x is _ _ _ _ (nearest integer)
[Given mass of
The deBroglie wavelength of
[28 Jan 2026 Shift 2]
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