JEE Main 28 June 2022 Shift 2 Solved Paper

Section: Chemistry

Question : 84 of 90

Marks: +1, -0

For the given reactions
Sn2++2e−→Sn
Sn4++4e−→Sn
the electrode potentials are ;ESn2+∕Sno=−0.140V and ESn4+∕Sno=−0.010V. The magnitude of standard electrode potential for Sn4+∕Sn2+ i.e. ESn4+∕Sn2+o is _____×10−2V. (Nearest integer)

[28-Jun-2022-Shift-2]

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