JEE Main 29-Jan-2024 Shift 1 Solved Paper

Section: Physics

Question : 37 of 90

Marks: +1, -0

The potential energy function (in J) of a particle in a region of space is given as U=(2x2+3y3+2z). Here x,y and z are in meter. The magnitude of x - component of force (in N ) acting on the particle at point P(1,2,3)m is :

[29-Jan-2024 Shift 1]

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