JEE Main 29-Jan-2024 Shift 1 Solved Paper

Section: Physics
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Question : 40 of 90
 
Marks: +1, -0
Match List I with List II
List I List II
A. ∮
→
B
⋅
→
dl
=µ0ic+µ0ε0‌
dφE
dt
I.
Gauss law for electricity
B. ∮
→
E
⋅
→
dl
=‌
dφB
dt
II. Gauss law for magnetism
C. ∮
→
E
⋅
→
dA
=‌
Q
ε0
III. Faraday law
D. ∮
→
B
⋅
→
dA
=0
IV.
Ampere -Maxwell law
Chose the correct answer from the options given below
[29-Jan-2024 Shift 1]
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