JEE Main 29 June 2022 Shift 2 Solved Paper

Section: Chemistry

Question : 85 of 90

Marks: +1, -0

The equation
k=(6.5×1012S−1)e−26000K∕T
is followed for the decomposition of compound A. The activation energy for the reaction is kJ‌mol−1. [nearest integer]
(Given : R=8.314JK−1mol−1 )

[29-Jun-2022-Shift-2]

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